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3b^2-8b=51
We move all terms to the left:
3b^2-8b-(51)=0
a = 3; b = -8; c = -51;
Δ = b2-4ac
Δ = -82-4·3·(-51)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-26}{2*3}=\frac{-18}{6} =-3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+26}{2*3}=\frac{34}{6} =5+2/3 $
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